Answer :

Given:


Angle of deflection, θ = 3.5°


Distance of the screen from the mirror, D = 1.5 m


The reflected rays get deflected by an amount twice the angle of deflection i.e.,


2θ = 7.0°


The displacement (d) of the reflected spot of light on the screen is given as:


tan2θ = d/1.5


(Using trigonometric ratio)


d = 1.5 x tan7o


d= 0.184 m = 18.4 cm


Hence, the displacement of the reflected spot of light is 18.4 cm


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