Answer :

As in question it is mentioned that all the H-atoms are in the ground state so radiation of frequency (E_{2}-E_{1})/h falling on it may be absorbed by some H-atoms and electron jumps to the next energy level i.e. first excited state (n=2). Now this frequency (E_{2}-E_{1})/h is sufficient to take the atom from n=1 to n=2 state. So saying that all atoms will be excited to the n = 2 state is wrong hence option (c) & (a) are wrong and also option (b) is correct.

Now from above it is obvious that electron jumps from E_{2} to E_{1} by radiating the energy of same frequency i.e. (E_{2}-E_{1})/h so electron from ground state will only jump to 1^{st} excited state (n=2) and no atoms will jump to 2^{nd} excited state (n=3). Hence option (d) is also correct.

Therefore option (b) & (d) are correct.

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