Q. 10

# It is found that |A+B|=|A|. This necessarily implies,A. B = 0B. A, B are antiparallelC. A, B are perpendicularD. A.B ≤ 0

We have to identity statements which are always true. It is given that , it could be true in two conditions that is either , which means option (a) and (b) might true.

For forming a single condition we will multiply them, as either one of them is true it will uphold the necessary condition

We know (from previous equations)

Therefore their magnitude’s product will also be zero.

(This will always be true)

Therefore,

(Equality is true for B=0)

Above condition is always true

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