Answer :
To Prove: 3 sin–1x = sin–1 (3x – 4x3)
Proof:
we know that,
sin3θ = 3 sinθ - 4 sin3θ.....(1)
Let sinθ = x, then
θ = sin-1 x
Put the value in equation 1, we get,
sin3θ = 3x - 4x3
3θ = sin-1(3x - 4x3)
3 sin–1x = sin–1 (3x – 4x3)
Hence, Proved.
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