Answer :

Let, sin x = t

Differentiating both side with respect to x


dt = cos x dx


At x = 0, t = 0


At x = π\2, t = 1



By using the concept of partial fraction



1 = A(1 + t) + B(2 + t)


1 = (A + 2B) + t(A + B)


A + 2B = 1, A + B = 0


A = -1, B = 1




y = [(-log 3 + log 2) – (-log 2 + log 1)]


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