Answer :

Let, Mass of the Hydrogen = m

Mass of the Chlorine = 35.5m

and given that, Separation between atoms = 1.27 Å

= 1.27×10-10 m

Let centre of mass for the molecule is a ‘x’ Å distance from the Cl atom then distance from Hydrogen atom be (1.27 – x) Å.

(As shown in the above diagram)

For one dimension, centre of mass CM can calculate by,


Where, m1 = mass of the first body,

m2 = mass of the second body,

x1 = Distance from centre of mass to the first body,

x2 = Distance from centre of mass to the second body,

Suppose Centre of mass of the molecule lies at origin (Zero) then,

( It is in 1 dimension)

1.27m – mx + 35.5mx = 0

1.27 – x = -35.5x

Å = -0.037 Å = -0.037×10-10 m

But, negative sign just indicates that CM lies left to chlorine (as assumed in figure) and it lies at a distance of 0.037×10-10 m.

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