Q. 13.8( 5 Votes )

Answer :

In the figure, the dotted circle is an equipotential surface due to the inner charge + Q.

The voltage at all points of an equipotential surface is the same (i.e. V_{A} = V_{B} = V_{C})

We know that work done by a point charge in moving from one point to another W = q × ΔV

Work done by moving a charge from A to B is W_{1} = q × (V_{A}-V_{B}) = 0

Work done by moving a charge from B to C is W_{2} = q × (V_{B}-V_{C}) = 0

Total work is done in moving a charge from A to B and then B to C is W_{1} + W_{2} = 0.

__Thus we can conclude that work done by moving a charge from one point to another on an equipotential surface is always zero.__

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A charge 'q' is moved from a point A above a dipole of dipole moment 'p' to a point B below the dipole in equatorial plane without acceleration. Find the work done in the process.

Physics - Board Papers