Q. 174.0( 4 Votes )

In the F2 generation of a Mendelian dihybrid cross the number of phenotypes and genotypes are:
A. phenotypes - 4; genotypes - 16

B. phenotypes - 9; genotypes - 4

C. phenotypes - 4; genotypes - 8

D. phenotypes - 4; genotypes - 9

Answer :

The F2 generation of a Mendelian dihybrid cross the number of phenotypes and genotypes are phenotypes-4; genotypes – 9.


For example consider the dihybrid cross between Round yellow(RRYY) and Wrinkled green(rryy) seed producing plants.


Gametes are RY and ry and the selfing of F1 generation(RrYy) we have:



Phenotypes obtained are round yellow, round green, wrinkled yellow, wrinkled green thus the number of phenotypes is 4.


Genotypes obtained are YYRR, YyRR, yyRR, YYRr,YyRr, yyRr, YYrr,Yyrr, rryy thus the number of phenotypes is 9.

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