Q. 30

# In the circuit sh

Given

Capacitance of capacitor C1 = 6C = 6μF

Capacitance of capacitor C2 = 3C = 3μF

Capacitance of capacitor C3 = 3C = 3μF

Voltage of battery E = 9V

When the switch K1 is closed and K2 is open, then the capacitors C1 and C �2 get charged and voltage V1 and V2 develops across the capacitors respectively. Applying Kirchhoff’s voltage law in the circuit, we get

We know that the charge stored in a capacitor and the voltage applied across it are related as:

Then for the capacitors C1 and C2,

Then from equations (1) and (2) we have

and

Now the charges on the capacitors

and

After this, when K1 was opened and K2 is closed the capacitor C2 becomes parallel to C3.

By conservation of charge we have

Where Q2’ is the new charge on capacitor C2 and Q3 is the charge flown from C2 to C3. Since they are connected in parallel, they have a common potential difference across them. Let the common potential be V’, then

Therefore, the charges on the capacitors are:

and

Therefore, the final charges on all the capacitors are:

,

and

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

In the circuit shPhysics - Exemplar

Convince yourselfHC Verma - Concepts of Physics Part 2

Each capacitor inHC Verma - Concepts of Physics Part 2

Each capacitor shHC Verma - Concepts of Physics Part 2

A cylindrical capHC Verma - Concepts of Physics Part 2

In the circuit shPhysics - Exemplar

A capacitor is maHC Verma - Concepts of Physics Part 2

Find the equivaleHC Verma - Concepts of Physics Part 2

A capacitor of caHC Verma - Concepts of Physics Part 2

A finite ladder iHC Verma - Concepts of Physics Part 2