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Q. 164.0( 8 Votes )

In double - slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1°. What is the spacing between the two slits?

Class 12th NCERT - Physics Part-II 10. Wave Optics

Answer :

Angular width is related to the slit spacing (d) as:

θ = λ/d

Thus,

d = λ/θ

Where,

λ is the wavelength of light

θ is the angular width of the fringe on the screen

d is the spacing between the two slits.

Given,

Wavelength of light, λ = 600 nm = 600 × 10 ^{- 9} m

The angular width of the fringe θ = 0.1^°

Note: The given angular width is in degrees, We must convert degrees into radiant for the angular width of the fringe.

Thus, Angular width, θ of the fringe can be written in radians as

⇒

d =

⇒ d = 3.44 × 10 ^{- 4} m

The spacing between the two slits “d” is 3.44 × 10 ^{- 4} m

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