Q. 115.0( 3 Votes )

In comparison to A. the same

B. about twice

C. about three times

D. about six times

Answer :

Depression in freezing point = i × m × Kf


Now, i = van’t Hoff factor, m is the molality and Kf is the freezing constant of the solvent.


Here, we see that molality is the same i.e. 0.01 M and Kf will be the same as the solvent is water.


Thus, depression in freezing point depends only on the van’t Hoff factor.


i = Total number of ions after dissociation/association/Total number of ions before dissociation/association.


i= 3 for MgCl2 as it dissociates into 3 ions


i = 1 for glucose as it does not undergo any association/dissociation.


Thus, option (iii) is the correct option.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A statement of asChemistry - Exemplar

Match the laws giChemistry - Exemplar