In comparison to A. the same

B. about twice

C. about three times

D. about six times

Depression in freezing point = i × m × K​_f

Now, i = van’t Hoff factor, m is the molality and K_f is the freezing constant of the solvent.

Here, we see that molality is the same i.e. 0.01 M and K_f will be the same as the solvent is water.

Thus, depression in freezing point depends only on the van’t Hoff factor.

i = Total number of ions after dissociation/association/Total number of ions before dissociation/association.

i= 3 for MgCl2 as it dissociates into 3 ions

i = 1 for glucose as it does not undergo any association/dissociation.

Thus, option (iii) is the correct option.