Q. 304.2( 6 Votes )

In an experiment,

Answer :

In first experiment:

Mass of barium sulphate = 1.288g


Mass of barium left = 1.03g


Mass of Sulphur present = 1.288 – 1.03 = 0.25g


Percentage of sulphur present in


Percenatage of sulphur is 20%


In second experiment:


Mass of barium sulphate = 3.672g


Mass of barium left = 2.938g


Mass of Sulphur present = 3.672 – 2.938 = 0.73g


Percentage of sulphur present


Percenatage of sulphur is 20%


In both the experiments, the percentage of sulphur is same.


Hence, it is verified that these figures verify the law of constant proportions.


Note: Law of constant proportions states that “in a chemical


substance, the elements are always present in definite


proportions by mass.


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