In an experiment,

In first experiment:

Mass of barium sulphate = 1.288g

Mass of barium left = 1.03g

Mass of Sulphur present = 1.288 – 1.03 = 0.25g

Percentage of sulphur present in

⇒ Percenatage of sulphur is 20%

In second experiment:

Mass of barium sulphate = 3.672g

Mass of barium left = 2.938g

Mass of Sulphur present = 3.672 – 2.938 = 0.73g

Percentage of sulphur present

⇒ Percenatage of sulphur is 20%

In both the experiments, the percentage of sulphur is same.

Hence, it is verified that these figures verify the law of constant proportions.

Note: Law of constant proportions states that “in a chemical

substance, the elements are always present in definite

proportions by mass.