Q. 244.0( 4 Votes )

# In an accelerator

Answer :

Given:

Total energy of system, E = 10.2 BeV = 10.2 × 109 × 1.6 × 10-19J

E = 16.32 × 10-10J

Energy in each ray, E’ = E/2

E’ = 8.16 × 10-10J

We know that Energy in a photon is given by, …(1)

Where,

E = Energy of photon

h = Planck’s constant = 6.6 × 10-34 Js

c = 3 × 108 ms-1

λ = wavelength of photon

From equation (1) we can get,  λ = 2.34 × 10-16m

Hence, the wavelength of each ray is 2.3 × 10-16 m.

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