Q. 145.0( 2 Votes )

# In a series LCR c

Answer :

Given: resistance R = 300Ω,

Capacitance of capacitor C = 20 μF,

Inductance of inductor L = 1.0 Henry,

Voltage across the circuit ϵ_{rms} = 50 V and

Frequency v = 50/π Hz

{a} rms current in the circuit will be

Where Z is impedance in the circuit

Then,

{b} potential difference across the capacitor will be

Potential difference across the resistor will be

Potential difference across the inductor will be

Net sum of all potential drops =

Rms voltage,

Hence, sum of all potential drops > rms potential applied.

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