Answer :

Given: resistance R = 300Ω,


Capacitance of capacitor C = 20 μF,


Inductance of inductor L = 1.0 Henry,


Voltage across the circuit ϵrms = 50 V and


Frequency v = 50/π Hz


{a} rms current in the circuit will be



Where Z is impedance in the circuit







Then,


{b} potential difference across the capacitor will be



Potential difference across the resistor will be



Potential difference across the inductor will be



Net sum of all potential drops =


Rms voltage,


Hence, sum of all potential drops > rms potential applied.


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