Q. 74.3( 59 Votes )

In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

Answer :

We know that,

ΔU = ΔH + W


Where ΔU is change in internal energy


Δ H is change in enthalpy


And W is work done on the system.


Given, 701 J of heat is taken by the system


Thus ΔH = 701 J


And 394 J of work is done by the system


Thus W = - 394


ΔU = 701 – 394


= 307 J


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