Q. 74.3( 59 Votes )
In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?
We know that,
ΔU = ΔH + W
Where ΔU is change in internal energy
Δ H is change in enthalpy
And W is work done on the system.
Given, 701 J of heat is taken by the system
Thus ΔH = 701 J
And 394 J of work is done by the system
Thus W = - 394
∴ ΔU = 701 – 394
= 307 J
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