Q. 74.2( 65 Votes )

In a process, 701

Answer :

We know that,

ΔU = ΔH + W

Where ΔU is change in internal energy

Δ H is change in enthalpy

And W is work done on the system.

Given, 701 J of heat is taken by the system

Thus ΔH = 701 J

And 394 J of work is done by the system

Thus W = - 394

ΔU = 701 – 394

= 307 J

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