Q. 30
In a photoelectri
Answer :
Given, stopping potential =2V
Work function Ф =4.5eV
Wavelength λ=200nm
∴ From Einstein’s photoelectric equation
∴ Minimum kinetic energy of photoelectron is 1.7eV
And maximum kinetic energy
[∵ Electric potential of 2V is applied for the electrons to
accelerate ∴ it is (2+1.7)]
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