Answer :

Consider a Parallelogram **KLMN**,

According to the problem, it is given that **∠****K = 60 ^{0}**.

We know that in a parallelogram,

⇒ The adjacent angles are supplementary.

⇒ The opposite angles are equal.

From the figure, we can say that,

**∠****K =** **∠****M** ...... - (1)

**∠****L =** **∠****N** ...... - (2)

**∠****K +** **∠****L = 180 ^{0}** (3)

From(1) we can write that

**∠****M = 60 ^{0}**

From(3) we can write that

⇒ 60^{0} + ∠L = 180^{0}

⇒ ∠L = 180^{0} - 60^{0}

⇒ **∠****L = 120 ^{0}**

From(2), we can say that

**∠****N = 120 ^{0}**.

The angles **∠****K,** **∠****L,** **∠****M,** **∠****N** are **60 ^{0}, 120^{0}, 60^{0}, 120^{0}**.

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