Answer :

Given,

Reverse saturation current (Io) = 5 × 10-12 A


Temperature (T) = 300K


The diode current (I) is given by the relation,



Where Io is the reverse saturation current


V is the voltage across the diode


kB is the Boltzmann’s constant


T is the absolute temperature


e is the electronic charge (1.6 × 10-19 C)


Note: The value of kB (in electron volts) is 8.6 × 10–5 eV/K and also 1.38 × 10-23 kg m2s-2K-1)


(a) For V = 0.6V,





So, I = 5.42 × 10-7 A


(b) For V = 0.7V,





So, I = 3.74 × 10-6 A


Hence, increase in current = 3.74 × 10-6 - 5.42 × 10-7 = 3.198 × 10-6 A


(c)


So, dynamic resistance =


i.e., Dynamic resistance = 31269.5 Ω = 31.26kΩ


(d) If the reverse bias voltage changes from 1V to 2V, then the diode current remains equal to reverse saturation current. So, dynamic resistance will be infinite.


NOTE: A diode is said to be in forward bias if the p-side and n-side are connected to the positive and negative terminals of the battery respectively. Electric current flowing through the diode in this condition is known as forward diode current. If the p-side is connected to the negative terminal and n-side is connected to the positive terminal of the battery, then the diode is said to be in reverse bias.


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