Answer :


Reverse saturation current (Io) = 5 × 10-12 A

Temperature (T) = 300K

The diode current (I) is given by the relation,

Where Io is the reverse saturation current

V is the voltage across the diode

kB is the Boltzmann’s constant

T is the absolute temperature

e is the electronic charge (1.6 × 10-19 C)

Note: The value of kB (in electron volts) is 8.6 × 10–5 eV/K and also 1.38 × 10-23 kg m2s-2K-1)

(a) For V = 0.6V,

So, I = 5.42 × 10-7 A

(b) For V = 0.7V,

So, I = 3.74 × 10-6 A

Hence, increase in current = 3.74 × 10-6 - 5.42 × 10-7 = 3.198 × 10-6 A


So, dynamic resistance =

i.e., Dynamic resistance = 31269.5 Ω = 31.26kΩ

(d) If the reverse bias voltage changes from 1V to 2V, then the diode current remains equal to reverse saturation current. So, dynamic resistance will be infinite.

NOTE: A diode is said to be in forward bias if the p-side and n-side are connected to the positive and negative terminals of the battery respectively. Electric current flowing through the diode in this condition is known as forward diode current. If the p-side is connected to the negative terminal and n-side is connected to the positive terminal of the battery, then the diode is said to be in reverse bias.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

(a) A student wanPhysics - Board Papers

(i) Explain with Physics - Board Papers

Write the two proPhysics - Board Papers

Name the junctionPhysics - Board Papers

Using a suitable Physics - Exemplar

What do the termsPhysics - Exemplar

<span lang="EN-USPhysics - Exemplar