Q. 185.0( 1 Vote )

# <span lang="EN-US

Potential barrier, d = 250 meV

Initially the kinetic energy of the hole = 300 meV

(a) When the hole approaches the junction from p-side, junction will act like forward biasing.

Therefore, the kinetic energy of the hole will decrease.

Final kinetic energy of the hole = (300-250) meV

= 50 meV

(b) When the hole approaches the junction from n-side, junction will act like reverse biasing.

Therefore, the kinetic energy of the hole in this case will increase.

Final kinetic energy of the hole = (300+250) meV

= 550 meV

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