Q. 185.0( 1 Vote )
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Answer :
Potential barrier, d = 250 meV
Initially the kinetic energy of the hole = 300 meV
(a) When the hole approaches the junction from p-side, junction will act like forward biasing.
Therefore, the kinetic energy of the hole will decrease.
Final kinetic energy of the hole = (300-250) meV
= 50 meV
(b) When the hole approaches the junction from n-side, junction will act like reverse biasing.
Therefore, the kinetic energy of the hole in this case will increase.
Final kinetic energy of the hole = (300+250) meV
= 550 meV
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