Q. 114.3( 28 Votes )

# In a chamber, a u

Answer :

Given:

Magnetic field strength, B = 6.5 G = 6.5 × 10^{-4}T

Initial velocity of electron = 4.8 × 10^{6} ms^{-1}

Angle between the initial velocity of electron and magnetic field, θ = 90^{0}

Force on the electron,

F_{e} = e × V × B × sinθ …(1)

Where,

e = charge on electron

V = velocity of electron

B = Magnetic field strength

θ = angle between direction of velocity and magnetic field

By putting the values in equation (1), we get

⇒ F_{e} = 1.6 × 10^{-19} C × 4.8 × 10^{6} ms^{-1} × 6.5 × 10^{-4}T × sin 90

⇒ F_{e} = 4.99 × 10^{-16}N

This force serves as the centripetal force, which explains the circular trajectory of the electron.

Centripetal force F_{c} = mv^{2}/r …(2)

By equating equation (1) and equation (2) we get,

⇒

⇒

r = 4.2 cm.

Hence the radius of the path of electron shot into the magnetic field is 4.2 cm.

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