Answer :

Given:


Magnetic field strength, B = 6.5 G = 6.5 × 10-4T


Initial velocity of electron = 4.8 × 106 ms-1


Angle between the initial velocity of electron and magnetic field, θ = 900



Force on the electron,


Fe = e × V × B × sinθ …(1)


Where,


e = charge on electron


V = velocity of electron


B = Magnetic field strength


θ = angle between direction of velocity and magnetic field


By putting the values in equation (1), we get


Fe = 1.6 × 10-19 C × 4.8 × 106 ms-1 × 6.5 × 10-4T × sin 90


Fe = 4.99 × 10-16N


This force serves as the centripetal force, which explains the circular trajectory of the electron.


Centripetal force Fc = mv2/r …(2)


By equating equation (1) and equation (2) we get,




r = 4.2 cm.


Hence the radius of the path of electron shot into the magnetic field is 4.2 cm.


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