Answer :

Given, yx = ey – x

Taking log both sides –

x log y = (y – x) loge e

x log y = y – x …(1)

y = x (1 + log y) …(2)

Differentiating w.r.t x, we get –

Applying product rule and chain rule of differentiation-

…[from eqn 1]

…[putting the value of y/x form (2)]

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