Answer :

Given, yx = ey – x


Taking log both sides –


x log y = (y – x) loge e


x log y = y – x …(1)


y = x (1 + log y) …(2)


Differentiating w.r.t x, we get –



Applying product rule and chain rule of differentiation-






…[from eqn 1]


…[putting the value of y/x form (2)]


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