Answer :

Magnification m = 375

Length of the tube L = 15 cm

Focal length of the objective f

We know that

Magnification m =

375 =

=

25 =

25f

23f

f

Length of the tube L = 15 cm

Focal length of the objective f

_{o}= 0.5 cmWe know that

Magnification m =

375 =

=

25 =

25f

_{e}= 50 + 2 f_{e}23f

_{e }= 50f

_{e}= 50/23 = 2.17 cm.Rate this question :

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