1.6A, 4A

Given,

Current through A1 ammeter, i-i1= 2.4A

Formula used:

Depending on the resistance offered by each paths of a circuit, the current split inversely. The voltage across the two branches will be same as they are connected parallel.

Solution:

The current going through Ammeter A3 will split into two. To find the current in two branches, let’s equate the voltage in each branches.

Hence,

By substituting the value of i-i1= 2.4A, we get i1 that goes through ammeter A2 as,

Hence the total current i, passing through A3

Hence the current through A2 and A3 are 1.6A and 4A.

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