# If the horizontal Where,

R=Normal reaction

θ=Angle of banking

v=velocity of the car

m=mass of the car

g= acceleration due to gravity

From the diagram, we can see that

R cosθ = mg

R sinθ = mv2/r

On dividing the above equations, we get

Tanθ = v2/rg

θ=tan-1(v2/rg)

We are given, v=10m/s

r=30m

θ=tan-1(10×10/30)

θ=tan-1(1/3)

Angle of banking should be tan-1(1/3)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

The <span lang="EPhysics - Exemplar

A <span lang="EN-Physics - Exemplar

A motorcycle is gHC Verma - Concepts of Physics Part 1

A simple pendulumHC Verma - Concepts of Physics Part 1

The center of a wHC Verma - Concepts of Physics Part 1

Water in a bucketHC Verma - Concepts of Physics Part 1

A stone of mass mHC Verma - Concepts of Physics Part 1

After a good mealHC Verma - Concepts of Physics Part 1

A car of mass M iHC Verma - Concepts of Physics Part 1

A person applies HC Verma - Concepts of Physics Part 1