Answer :

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Where,



R=Normal reaction


θ=Angle of banking


v=velocity of the car


m=mass of the car


g= acceleration due to gravity


r=radius


From the diagram, we can see that


R cosθ = mg


R sinθ = mv2/r


On dividing the above equations, we get


Tanθ = v2/rg


θ=tan-1(v2/rg)


We are given, v=10m/s


r=30m


θ=tan-1(10×10/30)


θ=tan-1(1/3)


Angle of banking should be tan-1(1/3)


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