# If the current I through a resistor is increased by 100% (assume that temperature remains unchanged), the increase in power dissipated will beA. 100 %B. 200 %C. 300 %D. 400 %

Case 1: power is given by

P1= I2R

Case 2: when current is increased by 100%

It means that current becomes doubled i.e. 2I

Power will be P2 = (2I)2R

i.e. Power = 4 I2R

Change in dissipated power = 4 I2R- I2R =3 I2R

Increase in percent of power dissipated = 3P1/P1 ×100% = 300%

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