Q. 124.4( 45 Votes )

# If the current I through a resistor is increased by 100% (assume that temperature remains unchanged), the increase in power dissipated will be

A. 100 %

B. 200 %

C. 300 %

D. 400 %

Answer :

Case 1: power is given by

P_{1}= I^{2}R

Case 2: when current is increased by 100%

It means that current becomes doubled i.e. 2I

Power will be P_{2} = (2I)^{2}R

i.e. Power = 4 I^{2}R

Change in dissipated power = 4 I^{2}R- I^{2}R =3 I^{2}R

Increase in percent of power dissipated = 3P_{1}/P_{1} ×100% = 300%

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