# If the capacitors in the previous question are joined in parallel, the capacitance and the breakdown voltage of the combination will beA. 2C and 2VB. C and 2VC. 2C and VD. C and V

Given:

Two capacitors of capacitance C each and breakdown voltage V connected in parallel Explanation:

The general formula for effective capacitance of a series combination of n capacitors is given by The equivalent capacitance of two capacitors connected in parallel are given by Where

C1 is the capacitance of the capacitor C1

C2 is the capacitance of the capacitor C2

Here C1=C2=C

Putting the values in the above formula, we get

Ceq=C+C=2C

Since, potential difference across capacitors in parallel are equal

Therefore voltage across the system is equal to the voltage across a single capacitor.

Therefore, breakdown voltage of the combination =V

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