Q. 33.7( 3 Votes )

If the capacitors in the previous question are joined in parallel, the capacitance and the breakdown voltage of the combination will be
A. 2C and 2V

B. C and 2V

C. 2C and V

D. C and V

Answer :

Given:

Two capacitors of capacitance C each and breakdown voltage V connected in parallel



Explanation:


The general formula for effective capacitance of a series combination of n capacitors is given by



The equivalent capacitance of two capacitors connected in parallel are given by



Where


C1 is the capacitance of the capacitor C1


C2 is the capacitance of the capacitor C2


Here C1=C2=C


Putting the values in the above formula, we get


Ceq=C+C=2C


Since, potential difference across capacitors in parallel are equal


Therefore voltage across the system is equal to the voltage across a single capacitor.


Therefore, breakdown voltage of the combination =V

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RELATED QUESTIONS :

In the circuit shown in Fig. 2.4. initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed (order is important).

[Take Q1’ and Q2’ as charges on C1 and C2 and V1 and V2 as voltage respectively.]



Then


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