# If the capacitors in the previous question are joined in parallel, the capacitance and the breakdown voltage of the combination will beA. 2C and 2VB. C and 2VC. 2C and VD. C and V

Given:

Two capacitors of capacitance C each and breakdown voltage V connected in parallel

Explanation:

The general formula for effective capacitance of a series combination of n capacitors is given by

The equivalent capacitance of two capacitors connected in parallel are given by

Where

C1 is the capacitance of the capacitor C1

C2 is the capacitance of the capacitor C2

Here C1=C2=C

Putting the values in the above formula, we get

Ceq=C+C=2C

Since, potential difference across capacitors in parallel are equal

Therefore voltage across the system is equal to the voltage across a single capacitor.

Therefore, breakdown voltage of the combination =V

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RELATED QUESTIONS :

In the circuit shown in Fig. 2.4. initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed (order is important).

[Take Q1’ and Q2’ as charges on C1 and C2 and V1 and V2 as voltage respectively.]

Then

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