Answer :
To prove: 
Given,
∵ sin(A+B) = sin A cos B + cos A sin B
∴ 
⇒ 
Applying componendo-dividendo rule, we get –
⇒ 
⇒ 
⇒ 
⇒ 
{∵ tan A = (sinA)/(cosA)}
⇒ 
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