Q. 505.0( 1 Vote )

If p and

Answer :


Given lines are xcosθ -ysinθ = -kcos2θ

And xsecθ +ycosecθ =k

Now, we find perpendicular of these lines from the origin

P = and q=

P=kcos2θ and q = kcosθ sinθ

P=kcos2θ and q =

Cos2θ = , q= i.e. sin2θ =

Since cos22θ +sin22θ =1

We have,

Or p2+4q2=k2

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