Q. 12 MCQ4.2( 17 Votes )

If momentum (P), A. (P1 A–1 T1)

B. (P2 A1 T1)

C. (P1 A–1/2 T1)

D. (P1 A1/2 T–1)

Answer :

According to question, momentum area and time are taken as fundamental quantities.


Now, we know that dimension of


Momentum(p)=


Area(A)=


Time (T)=


Energy=


Let us suppose,


E=


Now using principal of homogeneity, which states that the dimensions on both sides of a dimensional equation is same, we get


=




Equating the like terms we get


a=1, a+2b=2, -a+c=-2


1+2b=2, -1+c=-2


2b=1, c=-1


a=1, b=1/2, c=-1


Therefore,


E=


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