Q. 23.7( 3 Votes )

If heat is supplied to an ideal gas in an isothermal process,
A. the internal energy of the gas will increase

B. the gas will do positive work

C. the gas will do negative work

D. the said process is not possible.

Answer :

According to First law of thermodynamics,


ΔQ=ΔU+ΔW


Where ΔQ=heat supplied to the system


ΔU=change in internal energy


ΔW=work done by the system


For an isothermal process ΔT=0, therefore ΔU=0.


Then,


ΔQ=ΔW


When heat is supplied to the system gas expands i.e. the volume of the gas increases.


We know that,


Work done = force ×displacement



Volume = area ×displacement


Therefore,


Work done=pressure ×volume


Let change in the volume of object = ΔV = V2-V1


Pressure =P


Thus, work done by the object W


W=PΔV


During expansion volume increases. Hence, work done will be positive and equals PV.

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