Answer :

Given that,



x2+1 = x cos θ


x2- cos θx +1 = 0


We know that, b2-4ac ≥ 0


(-cos θ)2-4×1×1 ≥ 0


cos2θ -4 ≥ 0


cos2θ ≥ 4


cos θ ≥ ± 2


But -1 ≤ cos θ ≤ 1


So, no value of θ is possible

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