Q. 433.9( 12 Votes )

If 1 gram of sulphur dioxide contains x molecules, how many molecules will be present in 1 gram of oxygen?

(S = 32 u; O = 16 u)

Answer :

1 mole of SO2 = Mass of S + 2 × Mass of O = 64 grams

64 g of SO2 = 1 mole


So, 1 g of SO2 = 1/64 mole


Now since equal moles of all the substances contain equal number of molecules so, 1/64 mole of O2 will also contain x molecules like SO2.


32 g of oxygen = 1 mole


So, 1 g of oxygen = 1/32 mole


Now, 1/64 mole of oxygen contains = x molecules


So, 1/32 mole of oxygen will contain = x × 64/32 = 2x molecules


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