Q. 324.7( 15 Votes )

Identify the prod

Answer :

Propan-1-ol, when treated with concentrated sulphuric acid at 413K undergoes dehydration and forms protonated alcohol, which on further treatment with the alcohol forms an ether, 1-Propoxypropane. The mechanism followed is a nucleophilic bimolecular reaction (SN2) involving the attack of alcohol molecule on a protonated alcohol. Simple reaction is given as

The full reaction is carried out in three steps. The first step is protonation of propan-1-ol, the next is the nucleophilic attack by the protonated alcohol on another alcohol molecule. The final step is the deprotonation of the complex to form di-n-propyl ether.

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