Answer :

a. Fe + S FeS


In the given reaction, Fe is giving 2 electrons to Sulphur. Sulphur is accepting those electrons. This means:


Fe undergoes oxidation (to lose electrons)


Sulphur undergoes reduction (to accept electrons)


b. 2Ag2O 4 Ag + O2


Ag in Ag2O has oxidation state= +1


Ag in Ag(s) has oxidation state = 0


This means Ag undergoes reduction


O in Ag2O has oxidation state = -2


O in O2 has oxidation state = 0


This means oxygen undergoes oxidation


c. 2Mg + O2 2MgO


First write the half reactions:


Mg0 Mg2+ + 2e-


O2 + 4e- O2-


Oxygen goes from 0 to -2. Thus, it undergoes reduction.


Magnesium goes from 0 to +2. Thus, it undergoes oxidation


d. NiO + H2 Ni + H2O


First write the half reactions:


2H0 - 2e- 2H1


Ni2+ + 2e- Ni0


Hydrogen goes from 0 to 1. Thus, it undergoes oxidation.


Nickel goes from 2 to 0. Thus, it undergoes reduction.


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