Q. 164.0( 41 Votes )

# (i) The energy associated with the first orbit in the hydrogen atom is –2.18 × 10^{–18} J atom^{–1}. What is the energy associated with the fifth orbit?

(ii) Calculate the radius of Bohr’s fifth orbit for hydrogen atom.

Answer :

(i) Energy of an electrons = - (2.18× 10^{-18})/n^{2}

Where n = principal quantum number

Now the Energy associated with the fifth orbit of hydrogen atom is

E_{5} = -(2.18× 10^{-18})/(5)^{2} = -2.18× 10^{-18}/25

E_{5} = -8.72 × 10^{-20}J

(ii) Radius of Bohr’s n^{th} for hydrogen atom is given by,

R_{n} = (0.0529nm) / n2

For,

N = 5

R_{5} = (0.0529 nm) (5)^{2}

R_{5} = 1.3225 nm

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