Answer :

From the solar constant we deduce that

1.4 kW of power is incident upon every 1m2 of area.


i.e the total energy incident in 1 hr over an area of 1 m2 will be = 1.4 kW x 1 hr


(Since P=E/t or E=P x t)


Hence, energy = 1.4 kWh


Solar energy received by 1 m2 area in one hour (or 3600 s) = 1.4 x 3600 = 5040 kJ


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