Q. 24.5( 2 Votes )

How does th

Answer :

The electric flux on the enclosed spherical Gaussian surface is not affected by the change in radius of the spherical Gaussian surface.


The flux on the spherical Gaussian surface remains unchanged when we increase the radius of the Gaussian surface because the flux is independent of the change in radius of the surface. This can be seen in the following formula of the Gauss Law of Flux



where


is the electrical flux, Q is the charge on the spherical surface, is the permittivity of free space. As you can see from the formula that no mention of radius is done therefore there is no change.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

(a) Describe briePhysics - Board Papers

Repeat the previoHC Verma - Concepts of Physics Part 2

There is another Physics - Exemplar

Does the charge gPhysics - Board Papers