Q. 75.0( 2 Votes )

For the reaction<

Answer :

2N2O5(g) 4NO2(g) + O2(g)

The rate of the reaction is given by

Rate=1/2 {-Δ[N2O5]/ Δt}


{-Δ[N2O5]/ Δt} =1/2{[NO2 / Δt]}

= 2.8×10-3

× = =

The rate of disappearance = = 1.4 ×10-3M/sec

So, the rate of disappearance of N2O5 would be half of rate of production of NO2. So the rate of disappearance of N2O5 is 1.4 ×10-3M/sec

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