Q. 26

For the hydrolysi

Answer :

(a) [A]1= 0.1 mol L-1 at time = 0 seconds.


[A]2 = 0.05 mol L-1 at time = 10 seconds.


The rate constant (K) for a first order reaction is given as,


K =


K =


K = 0.069 sec-1


Now, at time = 20 s, [A]2 = 0.025 mol L-1


At time = 10 s, [A]1= 0.05 mol L-1


K =


K =


K = 0.069 sec-1


Since, the value of rate constant at any time is same i.e. 0.069sec-1. Therefore, the given reaction follows pseudo first order reaction.


(b) Average rate of reaction between the time intervals 10 to 20 seconds is


= =


= 0.0025 mol L-1 sec-1


OR


(a) For a reaction A + B P, the rate is given by


Rate = k [A][B]2


(i) If the concentration of B is doubled,


New rate of reaction, rate’ = k[A][2B]2


= 4k[A][B]


Rate’ = 4rate


The rate of reaction will become 4 times if the concentration of B is doubled.


(ii) Overall order of reaction if A is present in large excess will be 2. As A is present in large excess therefore the reaction will be independent of the concentration of A and will depend only on the concentration of B.


(b) Given, reaction is of 1st order,


t1/2 = 30 mins


K = = = 0.0231 min-1


[R] at 90% completion = [R0] - [R0] =


Time required for 90% completion of this reaction,


K =


t =


=


= 99.69 min


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