Q. 26

For the hydrolysi

(a) [A]1= 0.1 mol L-1 at time = 0 seconds.

[A]2 = 0.05 mol L-1 at time = 10 seconds.

The rate constant (K) for a first order reaction is given as,

K =

K =

K = 0.069 sec-1

Now, at time = 20 s, [A]2 = 0.025 mol L-1

At time = 10 s, [A]1= 0.05 mol L-1

K =

K =

K = 0.069 sec-1

Since, the value of rate constant at any time is same i.e. 0.069sec-1. Therefore, the given reaction follows pseudo first order reaction.

(b) Average rate of reaction between the time intervals 10 to 20 seconds is

= =

= 0.0025 mol L-1 sec-1

OR

(a) For a reaction A + B P, the rate is given by

Rate = k [A][B]2

(i) If the concentration of B is doubled,

New rate of reaction, rate’ = k[A][2B]2

= 4k[A][B]

Rate’ = 4rate

The rate of reaction will become 4 times if the concentration of B is doubled.

(ii) Overall order of reaction if A is present in large excess will be 2. As A is present in large excess therefore the reaction will be independent of the concentration of A and will depend only on the concentration of B.

(b) Given, reaction is of 1st order,

t1/2 = 30 mins

K = = = 0.0231 min-1

[R] at 90% completion = [R0] - [R0] =

Time required for 90% completion of this reaction,

K =

t =

=

= 99.69 min

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