(a) [A]0 = 0.01 Mol/L
[A] = 0.05 Mol/L at time t = 10s.
k = 0.0693 s-1
t = 20 s
K = 0.0693 s-1, Thus its pseudo first order reaction.
(b) The average rate constant is
= 0.0025 mol L-1s-1
(a) (i) Since the given reaction has order 2 with respect to reactant B, if the concentration of B is doubled in the given reaction, then the rate of reaction will become four times.
(ii) It the concentration of B is doubled i.e., [B]2 the overall reaction will be two, because if A is present in large excess, then the reaction will be independent of the concentration of A and will be dependent only on the concentration of B.
Order of reaction = 2.
(b) t1/2= 30 min
[R] = [R]0 – 90% of [R]0
t = 99.7 min.
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