In dilute sulphuric acid solution, hydrogen will be reduced at the cathodeand H2O is oxidized at anode.2H2O → O2 + 4H+ + 4e-while in a concentrated solution of sulphuric acid, SO2- ions are oxidized to tetrathionate ions.

Q. 5

for some half cel

Class 12th Chemistry - Exemplar 18. Model Question Paper-II

Answer :

In dilute sulphuric acid solution, hydrogen will be reduced at the cathode

and H₂O is oxidized at anode.

2H₂O → O₂ + 4H⁺ + 4e^-

while in a concentrated solution of sulphuric acid, SO₂^- ions are oxidized to tetrathionate ions.

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