The output ac voltage is 2.0 V.
The collector resistance of 2 KΩ
The base resistance is 1 KΩ
The current amplification factor = 100
the ac collector current ic = 2.0/2000 = 1.0 mA.
Current amplification factor, β= Ic / Ib
The signal current through the base is given by,
iB = 1 × 10-5 A
The input signal voltage is calculated as,
VBE=Ib × Rb =1× 10-5 × 1000= 10-2V
The input signal current is 0.01 mA or 10 μA.
Rate this question :