Answer :

The input signal voltage can be written as,


Vin = IBRB


Where,


IB is the base current ,


RB is the base resistance.


And we have,


β = IB / Ic


Where,


β is the current amplification factor ,


Ic is the collector current.


Given,


Collector resistance, Rc = 2 kΩ


Output voltage, V0 = 2 V


Base resistance, RB = 1 kΩ


Current amplification factor, β = 100


Thus,


we have base current ,


IB = VC / RCβ


IB = = 10 μA and


Input voltage as:


Vin = IBRB


Vin = 1000 Ω × 10 × 10-6 A


Vin = 10-2 V = 10 mV.


The base current is 10 μA and input voltage is 10 mV.


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