Answer :

Given that,

Rc = 2K-Ω = 2000 Ω (Collector Resistance)

V = 2 Volts (Audio signal voltage across the collector resistance)

β = 100 (Current amplification factor of the transistor)

RB = 1K-Ω (Base resistance)

Let, the Input signal voltage be Vi

Base current = IB

We have the relation for voltage amplification as:

Vi = 0.01 V

Therefore, the input signal voltage of the amplifier is 0.01 V.

We know that Base Resistance:

RB = Vi/IB

IB = Vi/RB = 0.01 V/1000Ω = 10μA

Therefore, the base current of the amplifier is 10μA

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