For a CE-transist

Given that,

R_c = 2K-Ω = 2000 Ω (Collector Resistance)

V = 2 Volts (Audio signal voltage across the collector resistance)

β = 100 (Current amplification factor of the transistor)

R_B = 1K-Ω (Base resistance)

Let, the Input signal voltage be V_i

Base current = I_B

We have the relation for voltage amplification as:

⇒

⇒

⇒V_i = 0.01 V

Therefore, the input signal voltage of the amplifier is 0.01 V.

We know that Base Resistance:

R_B = V_i/I_B

⇒ I_B = V_i/R_B = 0.01 V/1000Ω = 10μA

Therefore, the base current of the amplifier is 10μA