Answer :

Given that,


Rc = 2K-Ω = 2000 Ω (Collector Resistance)


V = 2 Volts (Audio signal voltage across the collector resistance)


β = 100 (Current amplification factor of the transistor)


RB = 1K-Ω (Base resistance)


Let, the Input signal voltage be Vi


Base current = IB


We have the relation for voltage amplification as:





Vi = 0.01 V


Therefore, the input signal voltage of the amplifier is 0.01 V.


We know that Base Resistance:


RB = Vi/IB


IB = Vi/RB = 0.01 V/1000Ω = 10μA


Therefore, the base current of the amplifier is 10μA


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