Q. 415.0( 2 Votes )

Fine the

Answer :


Any line parallel to 3x-4y+2=0 is 3x-4y+k=0

Now, it passes through (-2,3)

So, 3(-2)-4(3)+k=0

-6-12+k=0 k=8

Hence required equation is

3x-4y+18=0

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