Q. 24.5( 2 Votes )
Find the volume of CO2 at NTP obtained on heating 10 g of 90% pure limestone.
Chemical Formula of Limestone is CaCO3
Molecular Mass of Calcium Carbonate = 100 g/mol
10 grams of 100% pure of CaCO3 = 10gm of CaCO3
90% pure CaCO3 means, it will contain = of CaCO3
= 9 gm of CaCO3
Number of moles of CaCO3 =
= 0.09 mol
The reaction is given as follows:
Now according to the above reaction,
1 mole of CaCO3 gives 1 mole of CO2
So, 0.09 moles of CaCO3 will give 0.09 moles of CO2
Now according to the mole concept,
1 mole of CO2 will occupy 22.4 L by volume.
So, 0.09 moles of CO2 will occupy 22.4 × 0.09 L by volume
So total volume occupied = 2.016 L
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Calculate the amount of carbon dioxide that could be produced when
(i) 1 mole of carbon is burnt in air.
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
(iii) 2 moles of carbon are burnt in 16 g of dioxygen.NCERT - Chemistry Part-I