Q. 64.1( 19 Votes )

# Find the values o

Answer :

Given: 2x + 3y = 7 – eq 1

(a + b + 1)x + (a + 2b + 2)y = 4(a + b) + 1 – eq 2

Here,

a1 = 2, b1 = 3, c1 = - 7

a2 = (a + b + 1), b2 = (a + 2b + 2), c2 = - (4(a + b) + 1)

Given that system of equations has infinitely many solution = =  = = Here, = 3× - (4(a + b) + 1) = - 7×(a + 2b + 2)

- 12a - 12b - 3 = - 7a - 14b - 14

- 12a + 7a - 3 = 12b - 14b - 14

- 5a - 3 = - 2b - 14

5a - 2b - 11 = 0 eq 3

Also, = 2× - (4(a + b) + 1) = - 7×(a + b + 1)

- 8a – 8b – 2 = - 7a – 7b – 7

- 8a + 7a = 8b – 7b – 7 + 2

- a = b – 5

a + b = 5

a = 5 – b eq 4

substitute – eq 4 in – eq 3

5(5 – b) - 2b - 11 = 0

25 – 5b - 2b - 11 = 0

- 7b + 14 = 0

b = b = 2

substitute ‘b’ in – eq 4

a = 5 - 2

a = 3

a = 3, b = 2

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