Q. 2

# Find the values o

Given: (2a - 1)x + 3y = 5 – eq 1

3x + (b - 1)y = 2 – eq 2

Here,

a1 = (2a - 1), b1 = 3, c1 = - 5

a2 = 3 , b2 = (b - 1), c2 = - 2

Given that system of equations has infinitely many solution

= =

= =

Here,

=

- 2×(2a - 1) = 3×( - 5)

- 4a + 2 = - 15

- 4a = - 15 - 2

- 4a = - 17

b =

b = -

Also,

=

3( - 2) = - 5×(b - 1)

- 6 = - 5b + 5

5b = 5 + 6

5b = 11

b =

b =

a = , b =

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