Answer :

To find the total current(I) passing through the circuit, we must find the total resistance(R) and also we know the battery’s potential difference(V) which is 1.5 V , so by Ohm’s law we can find the net current flowing in the circuit.

As we can see by the figure that two resistors 1 ohm and 2 ohm are in series to each other, so we can directly add them , 1 + 2 = 3 ohm,

Also we can see that 3 resistors 4 ohm , 6 ohm , and 12 ohm are parallel to each other , so , let the net parallel resistance of these three resistors be R_{p} ,

Therefore, R_{p} = 2 ohm

Hence by Ohm’s law, V = I× R

As the current passing through 1 ohm resistor is the net current flowing in the circuit, so

V = I× R = 0.75× 1 = 0.75 V. It is the potential difference(V) across the 1 ohm resistor.

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