# Find the sum to μ terms of the series in Exercise 8 to 10 whose nth terms is given by n(n+1)(n + 4)

Tn = n(n+1)(n + 4)

Tn = n(n2+5n+4) = n3 + 5n2 + 4n

Sn = ∑ n3 + 5∑ n2 + 4∑ n

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